Sunday, November 28, 2010

Identifying Special Situations in Factoring

  • Difference of two squares
    • a2- b= (a + b)(a - b)
        • a2- 9 = (a + 3)(a - 3)
        • a2- 25 = (a + 5)(a - 5)
        • a2- 4 = (a + 2)(a - 2)
  • Trinomial perfect squares
    • a+ 2ab + b2= (a + b)(a + b) or (a + b)2
        • a+ 8a + 16= (a + 4)(a + 4) or (a +4)2
        • a+ 12a + 36= (a + 6)(a + 6) or (a + 6)2
        • a+ 10+25= (a + 5)(a + 5) or (a + 5)2
    • a- 2ab + b= (a - b)(a - b) or (a - b)2
        • a2 _ 6a + 9 = (a - 3)(a - 3) or (a - 3)2
        • a2 _ 10a + 25 = (a - 5)(a - 5) or (a - 5)2
        • a2 _ 8a + 16 = (a - 4)(a - 4) or (a - 4)2
  • Difference of two cubes
    • a3 - b3
    • 3 - cube root 'em
    • 2 - square 'em
    • 1 - multiply and change
        • a3 - 1 = (a - 1)(a2 + a + 1
        • a3 - 27 = (a - 3)(a2 + 3a + 6)
        • a3 - 64 = (a - 4)(a2 + 4a + 16)
  • Sum of two cubes
    • a3 + b3 
      • 3 - cube root 'em
      • 2 - square 'em
      • 1 - multiply and change
        • a3 + 1 = (a + 1)(a- a + 1)
        • a3 + 64 = (a + 4)(a2 - 4a + 16)
        • a3 + 125 = (a + 5)(a- 5a + 25)
    • Binomial Expansion
        • (a + b)3 = a3 + 3a2b + 3ab2 + b3= (a + 4) 3 = a3 + 12a2 + 48a + 64
        • (a + b)4 =a4 + 4a3b + 6a2b2 + 4ab3 + b4 = (a + 3) 4  = a4  + 12a3 + 54a2 + 108a + 81






                        

No comments:

Post a Comment